What is the vertex, axis of symmetry, the maximum or minimum value, and the range of parabola #f(x) = −4(x − 8)^2 + 3#?

1 Answer
May 3, 2015

#f(x)=-4(x-8)^2+3#
is a standard quadratic in vertex form:
#f(x) = m(x-a)^2+b#
where #(a,b)# is the vertex.

The fact that #m=-4<0# indicates that the parabola opens downward (the vertex is a maximum value)

The vertex is at #(8,3)#

Since it is a standard position parabola, the axis of symmetry is
#x=8#

The maximum value is #3#

The Range of #f(x)# is #(-oo,+3]#