# What is the vertex, axis of symmetry, the maximum or minimum value, and the range of parabola y=x^2-6x+2?

Jun 14, 2015

y = x^2 - 6x + 2

#### Explanation:

x of vertex = x of axis of symmetry = $x = \left(- \frac{b}{2} a\right) = \frac{6}{2} = 3$

y of vertex: y = f(3) = 9 - 18 + 2 = -7

Since a > 0. the parabola opens upward, there is a Min at
vertex (3, -7).

The range of the parabola: (-7, +infinity)