# What is the vertex, axis of symmetry, the maximum or minimum value, and the range of parabola #y=x^2-6x+2#?

##### 1 Answer

Jun 14, 2015

y = x^2 - 6x + 2

#### Explanation:

x of vertex = x of axis of symmetry =

y of vertex: y = f(3) = 9 - 18 + 2 = -7

Since a > 0. the parabola opens upward, there is a Min at

vertex (3, -7).

The range of the parabola: (-7, +infinity)