What is the vertex, axis of symmetry, the maximum or minimum value, and the range of parabola #y=x^2-6x+2#?
1 Answer
Jun 14, 2015
y = x^2 - 6x + 2
Explanation:
x of vertex = x of axis of symmetry =
y of vertex: y = f(3) = 9 - 18 + 2 = -7
Since a > 0. the parabola opens upward, there is a Min at
vertex (3, -7).
The range of the parabola: (-7, +infinity)
