What is the vertex of #f(x)=x^2-2x-3#?

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Answer 1 · 2015-04-12T20:03:51

You can complete the square like this: #f(x)=x^2-2x-3=x^2-2x+1-1-3=(x-1)^{2}-4# to see that the vertex is at the point #(x,y)=(1,-4)#.