Question

What is the vertex of `x = (2y + 3)^2 - 2`?

Answer 1

`(-2, -3/2)`

Explanation:

The given equation can be rewritten in a suitable form as follows:

`x= 4(y+3/2)^2 -2`

`1/4 x = (y+3/2)^2 -1/2`.

`1/4 ( x+2)= (y+3/2)^2`. The vertex may be read from this equation. It is `(-2, -3/2)`