# What is the vertex of  x = (2y + 3)^2 - 2 ?

Jan 19, 2016

$\left(- 2 , - \frac{3}{2}\right)$

#### Explanation:

The given equation can be rewritten in a suitable form as follows:

$x = 4 {\left(y + \frac{3}{2}\right)}^{2} - 2$

$\frac{1}{4} x = {\left(y + \frac{3}{2}\right)}^{2} - \frac{1}{2}$.

$\frac{1}{4} \left(x + 2\right) = {\left(y + \frac{3}{2}\right)}^{2}$. The vertex may be read from this equation. It is $\left(- 2 , - \frac{3}{2}\right)$