# What is the vertex of y = (1/2)(3x - 1)^2 + 3?

Nov 9, 2015

vertex $= \left(\frac{1}{3} , 3\right)$

#### Explanation:

If there is a coefficient in front of the x variable, always factor it out first. In this problem, factor out the 3:

$y = \left(\frac{1}{2}\right) \left({3}^{2}\right) {\left(x - \frac{1}{3}\right)}^{2} + 3$

Now, this is in vertex form:

vertex $= \left(\frac{1}{3} , 3\right)$

hope that helped