Question

What is the vertex of `y = (1/2)(3x - 1)^2 + 3`?

Answer 1

vertex `= (1/3, 3)`

Explanation:

If there is a coefficient in front of the x variable, always factor it out first. In this problem, factor out the 3:

`y=(1/2)(3^2)(x-1/3)^2+3`

Now, this is in vertex form:

vertex `= (1/3, 3)`

hope that helped