# What is the vertex of y=-1/2(x-4)^2-7?

Nov 5, 2014

$y = a {\left(x - h\right)}^{2} + k$,

where $\left(h , k\right)$ is the vertex.

Let us look at the posted problem.

Since

$a = - \frac{1}{2}$, $h = 4$, and $k = - 7$,

the vertex is $\left(4 , - 7\right)$.

I hope that this was helpful.