Vertex Form of a Quadratic Equation
Key Questions
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Answer:
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Please read the explanation.Explanation:
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Quadratic Equations in Vertex Form have a general form:color(red)(y=f(x)=a(x-h)^2+k , wherecolor(red)((h,k) is thecolor(blue)("Vertex" Let us consider a quadratic equation in Vertex Form:
color(blue)(y=f(x)=(x-3)^2+8 , wherecolor(green)(a=1; h=3; k=8 Hence,
color(blue)("Vertex "= (3, 8) To find the y-intercept, set
color(red)(x=0 y=(0-3)^2+8 y=9+8 y= 17 Hence, the y-intercept:
color(blue)((0, 17) We can use a table of values to draw the graph:
Use the table with two columns
color(red)(x and y to draw the graph as shown below:The Parent Graph of
color(red)(y=x^2 can also be seen for comparison, to better understand transformation.Also note that,
**Axis of Symmetry is **
color(red)(x=h rArr x= 3 We can verify this from the graph below:
Hope it helps.
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Since the equation is:
y=x^2+bx+c the vertex is
V(-b/(2a),-Delta/(4a)) ,or, found the
x_v=-b/(2a) you can substitue it in the equation of the parabola at the place ofx , finding they_v . -
Vertex Form
y=a(x-h)^2+k ,where
(h,k) is the vertex.
I hope that this was helpful.
Questions
Quadratic Equations and Functions
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Quadratic Functions and Their Graphs
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Vertical Shifts of Quadratic Functions
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Use Graphs to Solve Quadratic Equations
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Use Square Roots to Solve Quadratic Equations
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Completing the Square
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Vertex Form of a Quadratic Equation
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Quadratic Formula
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Comparing Methods for Solving Quadratics
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Solutions Using the Discriminant
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Linear, Exponential, and Quadratic Models
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Applications of Function Models