# What is the vertex of y= 1/4(2x+2)^2 - 8?

$\left(- 2 , - 8\right)$
When you have an equation in the form $y = a {\left(x + b\right)}^{2} + c$
thee vertex is given by $\left(- b , c\right)$
In this case it would be at $\left(- 2 , - 8\right)$