Question

What is the vertex of `y=-2(x+3)^2+1`?

Answer 1

(-3, 1)

Explanation:

(x + 3)² is a notable product, so we calculate it following this rule: First squared +(signal specified, + in this case) 2 x first x second + second squared: `x² + 2 . x . 3 + 9 = x² + 6x + 9`. Then, we insert it on the main equation: `y = -2(x+3)² + 1 = -2(x² + 6x +9) +1` , and it results in `y = -2x² -12x - 17`.
The x-vertix is found by taking : `-b / (2a) = -(-12)/(-4) = -3`.
The y-vertix is found by taking `-triangle/(4a) = - (b² - 4ac)/(4a) = - (144 - 136) / -8 = - (8)/-8 = - (-1) = 1`