# What is the vertex of y=-2(x+3)^2+1 ?

(x + 3)² is a notable product, so we calculate it following this rule: First squared +(signal specified, + in this case) 2 x first x second + second squared: x² + 2 . x . 3 + 9 = x² + 6x + 9. Then, we insert it on the main equation: y = -2(x+3)² + 1 = -2(x² + 6x +9) +1 , and it results in y = -2x² -12x - 17.
The x-vertix is found by taking : $- \frac{b}{2 a} = - \frac{- 12}{- 4} = - 3$.
The y-vertix is found by taking -triangle/(4a) = - (b² - 4ac)/(4a) = - (144 - 136) / -8 = - (8)/-8 = - (-1) = 1