# What is the vertex of y=2(x-3)^2+4?

Jan 4, 2016

$\left(3 , 4\right)$

#### Explanation:

This is in vertex form. Vertex form is a handy way of writing quadratic equations so that their vertices are evident from the equation itself and require no algebra to find.

Vertex form is:

$y = a {\left(x - h\right)}^{2} + k$

When $\left(h , k\right)$ is the vertex of the parabola.

The only tricky thing to watch out for is the $x$-coordinate. In vertex form, it's written as $- h$, so the actual $x$-coordinate $h$ will be the opposite of whatever is written inside the square term.

Thus,

$h = 3$
$k = 4$

The vertex is at $\left(3 , 4\right)$.

graph{2(x-3)^2+4 [-8.02, 14.48, -1.53, 9.72]}