# What is the vertex of # y= -(2x-1)^2-x^2-2x+3#?

##### 1 Answer

#### Explanation:

Let's expand everything we've got and see what we're working with:

*expand #(2x-1)^2#*

*distribute the negative*

*combine like-terms*

Now, let's rewrite the standard form into vertex form. To do that, we need to *complete the square*

*factor out the negative #5#*

Now we take the middle term (**but** we cannot randomly introduce a new value in this equation! What we can do is add

So, we have

*rewrite as a perfect square*

*combine constants*

*multiply #-11/25# by #-5# to remove one of the parentheses*

Now we've got the equation in vertex form.

From here, we can tell the vertex very easily:

Gives us