# What is the vertex of y=3x^2 +12x - 16 ?

Mar 6, 2018

$\left(- 2 , - 28\right)$

#### Explanation:

To find the x-coordinate of the vertex, you do $- \frac{b}{2 a}$

Where $a = 3 , b = 12 , c = - 16$

You then take that answer. Here that is $- \frac{12}{6} = - 2$, and then input that value as the $x$ value.

$3 {\left(- 2\right)}^{2} + 12 \left(- 2\right) - 6 = 12 - 24 - 16 = - 28$

So the coordinates are $\left(- 2 , - 28\right)$