What is the vertex of #y=4x-x^2#? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Mark D. Jun 23, 2018 (2,4) Explanation: #(-b)/(2a)# gives the X coordinate of the vertex #(-4)/(2xx-1)=(-4)/(-2)=2# Put x=2 into #y=4x-x^2# #y=4xx2-2^2# #y=8-4. => y =4# Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 1328 views around the world You can reuse this answer Creative Commons License