Question

What is the vertex of `y=(x-1) (x-2)+3x`?

Answer 1

`(0,2)`.

Explanation:

Simplifying `y=(x-1)(x-2)+3x=(x^2-3x+2)+3x`,

we get, `y=x^2+2, or, (y-2)=(x-0)^2`, showing that the

vertex is `(0,2)`.