# What is the vertex of  y= x^2– 12?

$\left(0 , - 12\right)$
This is really just the graph of $y = {x}^{2}$ shifted down by 12 units.
This means that for $y = {x}^{2} - 12 ,$ the vertex will be similar to that of $y = {x}^{2} ,$ with the $y -$coordinate being $12$ smaller.
The vertex of $y = {x}^{2}$ is $\left(0 , 0\right) .$ Here, the vertex is $\left(0 , 0 - 12\right) = \left(0 , - 12\right)$