Question

What is the vertex of `y= -x^2 + 12x + 36`?

Answer 1

`(6,72)`

Explanation:

Complete the square.

`y = -(x-6)^2 + 72`
graph{-(x-6)^2 + 72 [-20, 20, -80, 80]}
The vertex is the topmost point of the parabola.

Maximum occurs when `x=6`, and `y=72`.

The vertex is `(6,72)`.