Question

What is the vertex of `y= -x^2 + 12x +4`?

Answer 1

Find vertex of `y = -x^2 + 12x + 4`

Ans: Vertex (6, 40)

Explanation:

x-coordinate of vertex: `x = (-b)/(2a) = (-12)/-2 = 6`
y-coordinate of vertex: y = y(6) = - 36 + 72 + 4 = 40
Vertex (6, 40).