What is the vertex of # y= -x^2 - 2x - 3 #?

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Answer 1 · 2017-04-23T12:37:21

The vertex is #(-1,-2)#

To find the x coordinate, h, of the vertex, use the equation:

#h = -b/(2(a))#:

#h = -(-2)/(2(-1))#

#h = -1#

To find the y coordinate, k, of the vertex, evaluate the function at #x = h#:

#k = y(h)#

#k = y(-1)#

#k = -(-1)^2-2(-1)-3#

#k = -1+2-3#

#k = -2#

The vertex is #(-1,-2)#