# What is the vertex of  y= -x^2 - 2x - 3 ?

Apr 23, 2017

The vertex is $\left(- 1 , - 2\right)$

#### Explanation:

To find the x coordinate, h, of the vertex, use the equation:

$h = - \frac{b}{2 \left(a\right)}$:

$h = - \frac{- 2}{2 \left(- 1\right)}$

$h = - 1$

To find the y coordinate, k, of the vertex, evaluate the function at $x = h$:

$k = y \left(h\right)$

$k = y \left(- 1\right)$

$k = - {\left(- 1\right)}^{2} - 2 \left(- 1\right) - 3$

$k = - 1 + 2 - 3$

$k = - 2$

The vertex is $\left(- 1 , - 2\right)$