What is the vertex of # y= -x^2 + 2x - 7 #? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer ali ergin Mar 31, 2017 #"Vertex :"(1,-6)# Explanation: #"given function "y=-x^2+2x-7# #"derivate the function y with respect to x and make equal to zero."# #(d y)/(d x) =0# #d/(d x)(-x^2+2x-7)=0# #-2x+2=0# #-2x=-2# #x=2/2# #x=1# #"plug x=1 in the function " y=-x^2+2x-7 # #y=-1^2+2*1-7# #y=-1+2-7# #y=-6# Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 3709 views around the world You can reuse this answer Creative Commons License