# What is the vertex of  y=-x^2 + x - 5?

Mar 30, 2016

$V e r t e x \left(\frac{1}{2} , - \frac{19}{4}\right)$

#### Explanation:

x-coordinate of vertexL
$x = - \frac{b}{2 a} = - \frac{1}{-} 2 = \frac{1}{2}$
y-coordinate of vertex:
$y \left(\frac{1}{2}\right) = - \frac{1}{4} + \frac{1}{2} - 5 = - \frac{1}{4} - 5 = - \frac{19}{4}$
$V e r t e x \left(\frac{1}{2} , - \frac{19}{4}\right)$
graph{- x^2 + x - 5 [-20, 20, -10, 10]}