Question

What is the vertex of `y=-x^2 + x - 5`?

Answer 1

`Vertex (1/2, -19/4)`

Explanation:

x-coordinate of vertexL
`x = -b/(2a) = -1/-2 = 1/2`
y-coordinate of vertex:
`y(1/2) = - 1/4 + 1/2 - 5 = - 1/4 - 5 = - 19/4`
`Vertex (1/2, -19/4)`
graph{- x^2 + x - 5 [-20, 20, -10, 10]}