What is the vertex of y= x^2 - x - 6 ?

Apr 29, 2017

Vertex is $\left(0.5 , - 6.25\right)$

Explanation:

$y = {x}^{2} - x - 6$

Find the axis of symmetry first using the formula:

x = (-b)/(2a)" rarr x = (-(-1))/(2*1)

$x = \frac{1}{2}$

Then find $y$ by substituting $x = \frac{1}{2}$

$y = {\left(\frac{1}{2}\right)}^{2} - \frac{1}{2} - 6$

$y = - 6 \frac{1}{4}$

Vertex is $\left(0.5 , - 6.25\right)$