Question

What is the volume in mL of a 0.606 M KOH solution containing 0.023 mol of solute?

Answer 1

We use the quotient....`"Concentration"="Moles of solute"/"Volume of solution"'`

Explanation:

And thus `"Volume"="Moles of solute"/"Concentration"`

`=(0.023*cancel(mol))/(0.606*cancel(mol)*L^-1)=3.80xx10^-2*1/(1/L)=3.80xx10^-2*L`

And since there are `1000*mL*L^-1`, we gots a volume of `38*mL`.