Question

What is the volume occupied by 30.7 g `Cl_2`(g) at 35°C and 745 torr?

Answer 1

We use the old Ideal Gas Law, and get `V~=11*L`

Explanation:

We must first express the pressure exerted by the gas. We know that `1*atm` of pressure will support a column of mercury that is `760*mm` high. And thus a mercury column, even if you face an awful problem if the column breaks and the mercury spills, is a good visual representation of pressure.

And thus `1*atm-=760*mm*Hg`.......

And then we fill in the variables for `V=(nRT)/P`, i.e.

`V=((30.7*g)/(70.9*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx308.2*K)/((745*mm*Hg)/(760*mm*Hg*atm^-1))=??*L`

Is this expression dimensionally consistent? That is when I cancel out the units in the numerator and the denominator, I SHOULD get an answer in `L`...........All care taken but no responsibility admitted.