# What is the volume of 0..23 kg of pure water?

##### 1 Answer
Oct 16, 2016

$\text{Density"="Mass"/"Volume}$

Here, $\text{Volume}$ $=$ $230 \cdot m L$

#### Explanation:

So $\rho$ $=$ $\text{Density"="Mass"/"Volume}$

And of course, $\text{volume}$ $=$ $\frac{\text{Mass}}{\rho}$

For water, $\rho$ $=$ $1 \cdot g \cdot m {L}^{-} 1$

So $\text{volume}$ $=$ $\frac{0.23 \cdot \cancel{k g} \times {10}^{3} \cdot \cancel{g} \cdot \cancel{k {g}^{-} 1}}{1 \cdot \cancel{g} \cdot m {L}^{-} 1}$ $=$ $230 \left(\frac{1}{m {L}^{-} 1}\right)$ $=$ $230 \cdot m L$.