Question

What is the volume of 45.6 g of silver if the density of silver is 10.5 g/mL?

Answer 1

Simply solve the quotient: `(45.6*g)/(10.5*g*mL^-1)` `~=` `4*mL`

Explanation:

`rho,"density"` `=` `"Mass"/"Volume"`

And thus `"Volume"` `=` `"Mass"/rho` `=` `(45.6*cancelg)/(10.5*cancelg*mL^-1)` `=` `??mL`.

This is consistent dimensionally in that `1/(mL^-1)` `=` `1/(1/(mL))` `=` `1*mL` as required.