What is the volume of 45.6 g of silver if the density of silver is 10.5 g/mL?

1 Answer
Sep 24, 2016

Answer:

Simply solve the quotient: #(45.6*g)/(10.5*g*mL^-1)# #~=# #4*mL#

Explanation:

#rho,"density"# #=# #"Mass"/"Volume"#

And thus #"Volume"# #=# #"Mass"/rho# #=# #(45.6*cancelg)/(10.5*cancelg*mL^-1)# #=# #??mL#.

This is consistent dimensionally in that #1/(mL^-1)# #=# #1/(1/(mL))# #=# #1*mL# as required.