Question

What is the volume of 64 g of water?

Answer 1

`"Density, "rho_(H_2O)=1*g*mL,` or `1*g*cm^-3`

Explanation:

Now `rho="mass"/"volume"`

And thus `"volume"="mass"/rho=(64*cancelg)/(1*cancelg*mL^-1)`

`=(64)/(1/(mL))=64*mL`