# What is the VSEPR code and shape of N_2?

Each nitrogen atom ($Z = 7$) has $5$ valence electrons, giving 10 valence electrons in total. 4 of these electrons are presumed to form lone pairs on each nitrogen atoms; the remaining 6 electrons are shared between the nitrogen nuclei to form a very stable triple bond, $: N \equiv N :$. This triple bond accounts for the very short $N - N$ distance ($1.10 \times {10}^{- 10} m$), and the high bond dissociation energy of $226$ $k c a l \cdot m o {l}^{-} 1$.