What mass of solute is present in 250. mL of a 0.100 mol/L solution of NaOH (molar mass of NaOH = 40.000 g/mol)?

1 Answer
Sep 11, 2017

Answer:

#100*mg#.........

Explanation:

As with all these problems, we use the relationship.....

#"Concentration"-="Amount of solute"/"Volume of solution"#

And typically we report the molarity, where.....

#"Molarity"="Moles of solute (mol)"/"Volume of solution (L)"#

And thus the units of #"molarity"# are #mol*L^-1#.

And so....#"moles of solute"="Molarity"xx"Volume"#

#=0.100*mol*cancel(L^-1)xx250*cancel(mL)xx10^-3*cancel(L*mL^-1)#...

#=2.50xx10^-3*mol#

And this represents a mass of................

#2.50xx10^-3*molxx40.00*g*mol^-1=??*g#