# What's the geometry of the Ag_8GeS_6 molecule?

We suspect that we have $8 \times A {g}^{+}$ $+ 1 \times G {e}^{4 +}$ $+ 6 \times {S}^{2 -}$, ions, whose electronic sum is NEUTRAL as required. We could speculate that there is a ${\left[G e {S}_{6}\right]}^{8 -}$ OCTAHEDRON. And $8 \times A {g}^{+}$ counterions. This is about all we can say.