# What the is the polar form of y^2 = (x-1)^2/(y+x)-x^2 ?

Let $x = r \cos \left(\theta\right)$ and $y = r \sin \left(\theta\right)$
${r}^{2} {\sin}^{2} \left(\theta\right) = {\left(r \cos \left(\theta\right) - 1\right)}^{2} / \left(r \sin \left(\theta\right) + r \cos \left(\theta\right)\right) - {r}^{2} {\cos}^{2} \left(\theta\right)$
r^2(sin^2(theta)+cos^2(theta)) = (rcos(theta)-1)^2/(rsin(theta)+rcos(theta)
${r}^{3} = {\left(r \cos \left(\theta\right) - 1\right)}^{2} / \left(\sin \left(\theta\right) + \cos \left(\theta\right)\right)$