What the is the polar form of #y = y/x+(x-2y)^2 #?

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Noah G Share
Mar 10, 2018

We know that #x= rcostheta# and #y = rsintheta#.

#rsintheta = (rsintheta)/(rcostheta) + (rcostheta - 2rsintheta)^2#

#rsintheta = tan theta + r^2cos^2theta - 4r^2sinthetacostheta + 4r^2sin^2theta#

Hopefully this helps!

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