What the is the polar form of $y = y/x+(x-2y)^2$ ?

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Answer 1 · 2018-03-10T20:09:32

We know that $x= rcostheta$ and $y = rsintheta$ .

$rsintheta = (rsintheta)/(rcostheta) + (rcostheta - 2rsintheta)^2$

$rsintheta = tan theta + r^2cos^2theta - 4r^2sinthetacostheta + 4r^2sin^2theta$

Hopefully this helps!

What the is the polar form of y = y/x+(x-2y)^2 y = y/x+(x-2y)^2 ?