Question

What the is the polar form of `y = y/x+(x-2y)^2`?

Answer 1

We know that `x= rcostheta` and `y = rsintheta`.

`rsintheta = (rsintheta)/(rcostheta) + (rcostheta - 2rsintheta)^2`

`rsintheta = tan theta + r^2cos^2theta - 4r^2sinthetacostheta + 4r^2sin^2theta`

Hopefully this helps!