# What volume of 33% #"HCl"# required to neutralize 8000 gal of 50 % #"NaOH"#?

##### 2 Answers

#### Answer:

You will need to use 14 500 gal of 33 %

#### Explanation:

For purposes of calculation, I make several assumptions:

- Your percentages are mass percent.
- You are using Imperial gallons.
- The density of a 33 %
#"HCl"# solution is 1.164 kg/L. - The density of a 50 %
#"NaOH"# solution is 1.525 kg/L

**Step 1**: Use the balanced equation to get the **mass ratios**.

So, you need 36.46 kg of

**Step 2**: Calculate the mass of

**Step 3**: Calculate the mass of

**Step 4**: Calculate the volume of

You will need to use 14 500 gal of 33 %

#### Answer:

You will need to use 14 500 gal of 33 %

#### Explanation:

Let's solve this problem as if it were a titration calculation.

We will need the molarities of the

**Molarity of**

Assume that we have 1 L of the

**Molarity of**

Assume that you have 1 L of

**Titration Calculation**

The question is now, "What volume of 10.54 mol/L

Since 1 mol

or

The volume of