# When you square my value and subtract it from 23, the result is the square root of 36. I am an irrational number. What is my number?

Feb 9, 2016

The numbers are $\sqrt{17} \text{ and "sqrt(29)} 2$. As both 17 and 29 are prime numbers their roots are irrational.

#### Explanation:

Let the value be $v$

$\to 23 - {v}^{2} = \sqrt{36}$

$\to 23 - {v}^{2} = \pm 6$

${v}^{2} = 23 \pm 6$

$v = \pm \sqrt{17} \text{ or } v = \pm \sqrt{29}$

Both 17 and 29 are prime numbers therefore there roots irrational