# Which conic section has the polar equation r=1/(1-cosq)?

Apr 8, 2018

parabola

#### Explanation:

if you meant theta instead of q:

r=1/(1-cos(theta)

$r - r \cos \left(\theta\right) = 1$

$r = 1 + r \cos \left(\theta\right)$

$\sqrt{{x}^{2} + {y}^{2}} = 1 + x$

${x}^{2} + {y}^{2} = 1 + 2 x + {x}^{2}$

${y}^{2} = 1 + 2 x$

${y}^{2} / 2 - \frac{1}{2} = x$

^ a parabola opening to the right