# Which has a stronger polarising force Li^+ or Be^(2+)?

And of course the answer is $B {e}^{2 +}$ on both counts. And thus we predict that $B {e}^{2 +}$ is the stronger polarizer. I have no data with respect to $B e - C$ or $L i - C$ bond lengths. Dialkyl berylliums, the which would be fiendishly reactive, would tend to be more molecular than lithium alkyls, which are oligomeric.