Which of the following cations is least likely to form: #Sr^(2+)#, #Al^(3+)#, #K^(2+)#? Why?

1 Answer
Dec 15, 2016

Answer:

I would say #K^2#

Explanation:

Cations are ions with positive charges. #K# is in Group 1 of the periodic table, meaning it only needs to lose 1 electron in order to stabilize - as it has a charge of #1^+# Losing two electrons requires a lot of energy from #K# - meaning that it might not be a spontaneous reaction.