Why, in terms of atoms, are $C H_{3} C H_{2} O H$ $CH_3CH_2OH$ and $C H_{3} C H O$ $CH_3CHO$ not isomers of each other?

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Why, in terms of atoms, are $C H_{3} C H_{2} O H$ $CH_3CH_2OH$ and $C H_{3} C H O$ $CH_3CHO$ not isomers of each other?

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Answer 1 · 2017-06-04T22:55:28

Because they don't follow the definition of an isomer

Explanation:

Here is the Oxford Dictionary definition of an isomer
"Each of two or more compounds with the same formula but a different arrangement of atoms in the molecule and different properties."

$C H_{3} C H_{2} O H$ $CH_3CH_2OH$ has one more $O$ $O$ and $H$ $H$ than $C H_{3} C H O$ $CH_3CHO$

An example of an isomer is $C_{4} H_{8}$ $C_4H_8$ , as shown in this picture
![ www.chemguide.co.uk
It has the same amount of C and H atoms, but they're just arranged differently.

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Why, in terms of atoms, are $C H_{3} C H_{2} O H$ $CH_3CH_2OH$ and $C H_{3} C H O$ $CH_3CHO$ not isomers of each other?

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Explanation:

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Why, in terms of atoms, are CH_3CH_2OHCH3CH2OHCH_3CH_2OH and CH_3CHOCH3CHOCH_3CHO not isomers of each other?

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Explanation:

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Why, in terms of atoms, are $C H_{3} C H_{2} O H$ $CH_3CH_2OH$ and $C H_{3} C H O$ $CH_3CHO$ not isomers of each other?