# Write the complex number (2-3i)(-1+4i) in standard form?

$\left(2 - 3 i\right) \left(- 1 + 4 i\right) = - 2 + 8 i + 3 i - 12 {i}^{2} =$
But ${i}^{2} = {\left(\sqrt{- 1}\right)}^{2} = - 1$
$= - 2 + 11 i + 12 = 10 + 11 i$