Write the complex number #(3+10i)^2# in standard form? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer GiĆ³ May 11, 2015 You can write it as: #(3+10i)(3+10i)=# multiply the two brackets: #=9+30i+30i+100i^2=# But #i^2=(sqrt(-1))^2=-1# so: #=9+60i-100=-91+60i# Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 3308 views around the world You can reuse this answer Creative Commons License