You used 1.01 g of solid and it required 15.00 ml of 1.00 M HCL to reach the endpoint. determine the no of moles of hcl in your titration?

1 Answer
Mar 12, 2018

Answer:

You must have seen the expression..#"concentration"="moles of solute"/"volume of solution"#

Explanation:

And given the quotient....we use....

#"moles of solute"="concentration"xx"volume of solution"#

And so ................

#n_"HCl"=15.00*mLxx10^-3*L*mL^-1xx1.00*mol*L^-1=0.0150*mol#

....and thus the #1.01*g# mass represents this molar equivalence....