How do I use the quadratic formula to solve #x^2+3x-2=0#?

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Answer 1 · 2014-09-30T03:31:28

#ax^2+bx+c=0#

#x^2+3x-2=0#

#a=1, b=3, c=-2#

Quadratic formula

#x=(-(3)+-sqrt((3)^2-4(1)(-2)))/(2(1))#

#x=(-3+-sqrt(9+8))/2#

#x=(-3+-sqrt(17))/2#