How do you write #-5x+12=20# in slope intercept form?

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Answer 1 · 2014-11-28T20:57:52

#-5x+12=20#

by subtracting #12#,

#=> -5x=8#

by dividing by #-5#,

#=> x=-8/5#,

which is a vertical line, whose slope is undefined, so it cannot be written in Slope-Intercept Form.

I hope that this was helpful.