How do I find the binomial expansion of #(1+12x)^(3/4)#? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer vince Feb 21, 2015 Use the general formula #(1+X)^\alpha = \sum_{n=0}^\infty (alpha(alpha-1)(alpha -2) ... (alpha -n +1))/(n!) X^n# #(1+X)^\alpha = 1 + alpha X + (alpha (alpha -1))/2 X^2 + (alpha (alpha -1)(alpha-3))/6 X^3 + ...# with #alpha = 3/4# and #X = 12x#. Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 2182 views around the world You can reuse this answer Creative Commons License