Question

How do you calculate the derivative for `g(t)= 7/sqrtt`?

Answer 1

You can rewrite the equation `g(t)=7*t^(-1/2)`

Minus because it's under the bar, 1/2 because it's a square root.

Then it's the recipe: one off the power, multiply by the power:

`g'(t)=7*(-1/2)*t^(-1 1/2)=7/(2*t sqrtt`