How do you convert $8 x - 4 y = 16$ $8x - 4y = 16$ into slope intercept form?

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Answer 1 · 2015-04-03T17:22:15

y= 2x-4

Rewrite the given equation as 4y= 8x-16 and divide by 4 on both sides to have y=2x-4. This is the required slope intercept form

Answer 2 · 2015-04-03T17:23:24

The slope-intercept form is $y = m x + n$ $y=mx+n$

$8 x - 4 y = 16$ $8x-4y=16$

$4 y = 8 x - 16$ $4y=8x-16$

$y = \frac{8}{4} x + \frac{16}{4}$ $y = 8/4x+16/4$

$y = 2 x + 4$ $y=2x+4$

How do you convert 8x−4y=168x - 4y = 16 into slope intercept form?