How do you graph the inequality #2x + 3y > 6#?

1 Answer
Bill K.
Apr 6, 2015

First draw a lightly dashed version of the line #2x+3y=6#, which is equivalent to #y=-\frac{2}{3}x+2# (a line with a slope of #-2/3# and a #y#-intercept of #y=2#...also note that the #x#-intercept is #x=3#).

Next, note that the point #(0,0)# does not satisfy the inequality #2x+3y>6#. Therefore, shade in the "half-plane" on the other side of the line #2x+3y=6# from the side that #(0,0)# is on. Make sure the line #2x+3y=6# remains lightly dashed. It's not part of the solution set.

Related questions
See all questions in Linear Inequalities in Two Variables
Impact of this question
10520 views around the world
You can reuse this answer
Creative Commons License