Question

How do you factor completely `x^3-4x^2-2x+8`?

Answer 1

The passages to do are:

`x^3-4x^2-2x+8=x^2(x-4)-2(x-4)=(x-4)(x^2-2)`

and... if you want:

`=(x-4)(x+sqrt2)(x-sqrt2)`