Question

Question #a77a0

Answer 1

The volume is 40.6 L.

The temperature remains constant while `P` and `V` change.

This is a Boyle's Law problem.

`(P_1V_1)/T_1=(P_2V_2)/T_2`

`P_1 = "2.00 atm"`; `V_1 = "20.3 L"`
`P_2 = "1.00 atm"`; `V_2 = "?"`

`V_2 = "20.3 L" × (2.00 cancel("atm"))/(1.00 cancel("atm")) = "40.6 L"`

The volume of the gas is 40.6 L