Question

How do you solve `sqrtx+12=x`?

Answer 1

Take `12` to the right and then square both sides to get:
`x=(x-12)^2`
`x=x^2-24x+144`
`x^2-25x+144=0`
Solve for `x` and then check the results (you´ll get 2 of which only one acceptable) by substituting back into your original equation.