How do you determine the amplitude and period for $y = - \frac{2}{4} cos (\frac{7}{2})$ $y = -2/4 cos (7/2)$ ?

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How do you determine the amplitude and period for $y = - \frac{2}{4} cos (\frac{7}{2})$ $y = -2/4 cos (7/2)$ ?

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Answer 1 · 2015-04-19T14:13:01

I think you missed an $x$ $x$ (in the argument of $cos$ $cos$ I think).
If it is: $y = - \frac{1}{2} cos (\frac{7}{2} x)$ $y=-1/2cos(7/2x)$

The amplitude is given by the number in front of $cos$ $cos$ , i.e., $- \frac{1}{2}$ $-1/2$ ( $cos$ $cos$ oscillates between $\frac{1}{2}$ $1/2$ and $- \frac{1}{2}$ $-1/2$ ) while the period is given by the coefficient, $\frac{7}{2}$ $7/2$ , in front of $x$ $x$ as:
$\frac{7}{2}$ $7/2$ = $2 π$ $2pi$ /period;

Giving: period= $\frac{4}{7} π$ $4/7pi$

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How do you determine the amplitude and period for $y = - \frac{2}{4} cos (\frac{7}{2})$ $y = -2/4 cos (7/2)$ ?

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