How do you determine the amplitude and period for #y = -2/4 cos (7/2)#?

1 Answer
Apr 19, 2015

I think you missed an #x# (in the argument of #cos# I think).
If it is: #y=-1/2cos(7/2x)#

The amplitude is given by the number in front of #cos#, i.e., #-1/2# ( #cos# oscillates between #1/2# and #-1/2#) while the period is given by the coefficient, #7/2#, in front of #x# as:
#7/2#=#2pi#/period;

Giving: period=#4/7pi#